-0.03x^2-0.8x+9.75=x

Solution for -0.03x^2-0.8x+9.75=x equation:

-0.03x^2-0.8x+9.75=x

We move all terms to the left:

-0.03x^2-0.8x+9.75-(x)=0

We add all the numbers together, and all the variables

-0.03x^2-1.8x+9.75=0

a = -0.03; b = -1.8; c = +9.75;
Δ = b2-4ac
Δ = -1.82-4·(-0.03)·9.75
Δ = 4.41
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-1.8)-\sqrt{4.41}}{2*-0.03}=\frac{1.8-\sqrt{4.41}}{-0.06}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-1.8)+\sqrt{4.41}}{2*-0.03}=\frac{1.8+\sqrt{4.41}}{-0.06}
$